+0

# math problem

0
326
3

hey all! what is x in this? 1/sqrt(x^7

Aug 30, 2017

#3
+27396
0

Like so:  $$\frac{1}{\sqrt{x^7}}\rightarrow \frac{1}{x^{7/2}} \rightarrow x^{-7/2}$$

.

Aug 30, 2017

#1
+558
0

x > 0?

Because the denominator should not be 0, or else there wouldn't be any real solutions.

Correct me if I'm wrong.

(My brain is a bit fuzzy these days. I haven't answered a math question for a while...)

Aug 30, 2017
#2
0

x should be something like x^(1/4) for example, it has to be positive cause its one of my math tasks that i just cant understand :D

Aug 30, 2017
#3
+27396
0
Like so:  $$\frac{1}{\sqrt{x^7}}\rightarrow \frac{1}{x^{7/2}} \rightarrow x^{-7/2}$$