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What is the smallest positive integer that can be added to the sum of consecutive integers

1 + 2 + 3 + ... + 327 + 328 + 329

so that the resulting total is divisible by 5?

 Mar 6, 2022
 #1
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Sum==[329  x  330] / 2 ==54,285

 

Since the sum ends in 5, that means it is already divisible by 5, and there is no need to add anything to it. You can add zero to it if you wish, but it has no meaning.

 Mar 6, 2022
 #2
avatar+36435 
+1

Since it is already divisible by 5 , the smallest positive integer you could add to it would be '5' to still be divisible by 5 .

 Mar 6, 2022

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