Four years ago Arthur is 11 times as old as his son Arthur Jr, but four years from now, Arthur will only be \(4\) times as old as Jr. What is Arthur’s age when he is twice as old as Arthur Jr?
+37153 a = arthur now
(a-4) = 11 (j-4) and (a+4) = 4 (j+ 4)
a = 11j -40 11j-40 + 4 = 4j+ 16 shows j = 8 then a = 48
now find when he is twice as old as j
a + x = 2 ( j+x)
48 + x = 2(8) + 2x
32 = x 32 years from now arthur = 80 j = 40 y/o
EP: Your 2 equations: (a-4) = 11 (j-4), (a+4) = 4 (j+ 4), solve for a, j give the following fractional results:
a = 292/7 and j = 52/7 [I think there is a mistake in the question] !!
+37153 Yep, I believe you are correct..... there is a problem with the Q AND my solution had a math error ! D'Oh ! 
~ EP
Let's use the correct numbers (thanx , Guest !)
a = arthur now
(a-4) = 11 (j-4) and (a+4) = 4 (j+ 4)
a = 11j -40 11j-40 + 4 = 4j+ 16 shows j = 52/7 then a = 292/7
check: 4 years ago j = 24/7 a = 264/7 CHECK !
check 4 years from now j = 80/7 a = 320/70 CHECK !
Now find when a is twice as old
11j-40 + x = 2 ( j+x)
11(52/7) - 40 + x = 104/7 + 2x
188/7 = x 188/7 years from now a will be twice as old as j CHECK !
