The positive five-digit integers that use each of the digits 1, 2, 3, 4 and 5 exactly once are ordered from least to greatest. What is the 60th integer in the list?
5!=120
so it looks like you want the middle one.
so it will start with a 3
How many are less than 30000? That would be 2*4!=48
how many start with 31? That would be 3! = 6
So another 6 will start with 32
So that means there are 60 that are less than 34000
So the 60th one must be 32541