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# Math Question Help - No Need to Rush

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Compute $$\binom40+\binom51+\binom62+\binom73.$$

I'm not sure how to solve these binomial expressions.

Apr 9, 2019

### 3+0 Answers

#1
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$$\dbinom{n}{k} = \dfrac{n!}{k!(n-k)!}\\ n! = n \cdot (n-1) \cdot (n-2) \cdot \dots \cdot 3 \cdot 2$$

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Apr 9, 2019
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Thanks!

detkitten  Apr 9, 2019
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Note that

C(n,m) + C(n + 1, m + 1) + C(n + 2, m + 2)  + .....+ C( n + q, m + q)  =  C (n + q + 1, m + q)

So

C(4,0)  + C(5, 1) + C(6,2) + C(7, 3)  = C(8, 3)   =   56

Apr 9, 2019