+349 So, \(a+b=16\) (A) and \(a*b=192\). (B).
Multiply \(b\) to both sides of (A): \(ab+b^2=16b\).
Subtract the two equations together: \(b^2=16b-192\).
Turn it into standard form of a quadratic: \(b^2-16b+192=0\).
Unfortunately, this doesn't have any real solutions, but I'll show the complex ones anyway. \(b={16\pm16i\sqrt{2}\over 2}=8\pm8i\sqrt{2}\)
Substituting this into (A) gets us: \(a+8\pm8i\sqrt{2}=16\).
Subtract 8 from both sides: \(a\pm8i\sqrt{2}=8\).
Isolate a: \(a=8\mp8i\sqrt{2}\).
QUICK CHECK:
\(8\mp8i\sqrt{2}+8\pm8i\sqrt{2}=16?\)
Plus-minus and minus-plus cancel out: \(8+8=16\), \(16=16\)
\((8\mp8i\sqrt{2})(8\pm8i\sqrt{2})=192?\)
Product of sum and difference: \(8^2-(8i\sqrt{2})^2=64-8^2i^2\sqrt{2}^2=64-(-128)=192\) 
+349 So, \(a+b=16\) (A) and \(a*b=192\). (B).
Multiply \(b\) to both sides of (A): \(ab+b^2=16b\).
Subtract the two equations together: \(b^2=16b-192\).
Turn it into standard form of a quadratic: \(b^2-16b+192=0\).
Unfortunately, this doesn't have any real solutions, but I'll show the complex ones anyway. \(b={16\pm16i\sqrt{2}\over 2}=8\pm8i\sqrt{2}\)
Substituting this into (A) gets us: \(a+8\pm8i\sqrt{2}=16\).
Subtract 8 from both sides: \(a\pm8i\sqrt{2}=8\).
Isolate a: \(a=8\mp8i\sqrt{2}\).
QUICK CHECK:
\(8\mp8i\sqrt{2}+8\pm8i\sqrt{2}=16?\)
Plus-minus and minus-plus cancel out: \(8+8=16\), \(16=16\)
\((8\mp8i\sqrt{2})(8\pm8i\sqrt{2})=192?\)
Product of sum and difference: \(8^2-(8i\sqrt{2})^2=64-8^2i^2\sqrt{2}^2=64-(-128)=192\)
