+52 A rectangular piece of metal is 25 in longer than it is wide. Squares with sides
5in long are cut from the four corners and the flaps are folded upward to form an open box. If the volume of the box is 750in cubed3,what were the original dimensions of the piece of metal?
What is the original width? in
+9481 
Imagine folding this up like it says in the problem...we can see that
height of box = 5
width of box = w - 5 - 5 = w - 10
length of box = (w + 25) - 5 - 5 = w + 15
volume of box = (height)(width)(length)
750 = (5)(w - 10)(w + 15)
750/5 = (w - 10)(w + 15)
150 = w2 + 5w - 150
0 = w2 + 5w - 300
0 = (w + 20)(w - 15)
w = -20 or w = 15
So...the original width must be 15 in. 
+9481
Imagine folding this up like it says in the problem...we can see that
height of box = 5
width of box = w - 5 - 5 = w - 10
length of box = (w + 25) - 5 - 5 = w + 15
volume of box = (height)(width)(length)
750 = (5)(w - 10)(w + 15)
750/5 = (w - 10)(w + 15)
150 = w2 + 5w - 150
0 = w2 + 5w - 300
0 = (w + 20)(w - 15)
w = -20 or w = 15
So...the original width must be 15 in.
