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What is a 9 digit number using digits 1-9 that is divisible by 9, if you take away the last digit is divisible by 8 etc

 Apr 27, 2014

Best Answer 

 #1
avatar+6250 
+5

you can build this up from the left

one such number is

123654321

$${\frac{{\mathtt{123\,654\,321}}}{{\mathtt{9}}}} = {\mathtt{13\,739\,369}}$$

$${\frac{{\mathtt{12\,365\,432}}}{{\mathtt{8}}}} = {\mathtt{1\,545\,679}}$$

$${\frac{{\mathtt{1\,236\,543}}}{{\mathtt{7}}}} = {\mathtt{176\,649}}$$

$${\frac{{\mathtt{123\,654}}}{{\mathtt{6}}}} = {\mathtt{20\,609}}$$

$${\frac{{\mathtt{12\,365}}}{{\mathtt{5}}}} = {\mathtt{2\,473}}$$

$${\frac{{\mathtt{1\,236}}}{{\mathtt{4}}}} = {\mathtt{309}}$$

$${\frac{{\mathtt{123}}}{{\mathtt{3}}}} = {\mathtt{41}}$$

$${\frac{{\mathtt{12}}}{{\mathtt{2}}}} = {\mathtt{6}}$$

$${\frac{{\mathtt{1}}}{{\mathtt{1}}}} = {\mathtt{1}}$$

if you just work this backwards you can see how it's constructed.  Just make sure your condition is met each time you add a new digit.

 Apr 28, 2014
 #1
avatar+6250 
+5
Best Answer

you can build this up from the left

one such number is

123654321

$${\frac{{\mathtt{123\,654\,321}}}{{\mathtt{9}}}} = {\mathtt{13\,739\,369}}$$

$${\frac{{\mathtt{12\,365\,432}}}{{\mathtt{8}}}} = {\mathtt{1\,545\,679}}$$

$${\frac{{\mathtt{1\,236\,543}}}{{\mathtt{7}}}} = {\mathtt{176\,649}}$$

$${\frac{{\mathtt{123\,654}}}{{\mathtt{6}}}} = {\mathtt{20\,609}}$$

$${\frac{{\mathtt{12\,365}}}{{\mathtt{5}}}} = {\mathtt{2\,473}}$$

$${\frac{{\mathtt{1\,236}}}{{\mathtt{4}}}} = {\mathtt{309}}$$

$${\frac{{\mathtt{123}}}{{\mathtt{3}}}} = {\mathtt{41}}$$

$${\frac{{\mathtt{12}}}{{\mathtt{2}}}} = {\mathtt{6}}$$

$${\frac{{\mathtt{1}}}{{\mathtt{1}}}} = {\mathtt{1}}$$

if you just work this backwards you can see how it's constructed.  Just make sure your condition is met each time you add a new digit.

Rom Apr 28, 2014
 #2
avatar+118613 
0

COOL !    THANKS ROM!

 

I LIKED THE QUESTION TOO!

 Apr 28, 2014

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