my friend shared this riddle with me, and it was cool so i wanted to share it with you guys
In a pond there are some flowers with some bees hovering over them. How many flowers and bees are there if both the following statements are true: 1. If each bee lands on a flower, one bee doesn’t get a flower. 2. If two bees share each flower, there is one flower left out.
Although the answer is simple and you can guess it ver fast, here is an equation you can set up
EDIT: LOL this is incorrect now I am going to ask the question: Why doesn't my strategy work?
x = bees
y = flowers
x = y + 1
x = 2y - 1
This is because for statement 1, notice how there are one more bees than the number of flowers
and for statement 2, the flowers would have to be doubled and have one flower subtracted from that in order to equal the amount of bees
So the answer is 2 flowers and 3 bees.
I got 4 and 3
Let x = the number of bees and y the number of flowers
In the first equation....we have one more bee than the number of flowers so
x - 1 = y (1)
In the second equation, x/2 = the number of flowers occupied by bees.....and if we add 1 to this,we get the total number of flowers....so
x/2 + 1 = y ⇒ -x/2 - 1 = -y (2)
Add (1) and (2) and we have that
(1/2)x - 2 = 0
(1/2)x = 2
x = 4
And y = 4 - 1 = 3