A set of six distinct positive integers has a mean of 8, a median of 8 and no term greater than 13. What is the least possible value of any term in the set?
first we have 8*6 as the total value of the set of number (no.)
and we have 8 as the medium of the set of no.,so the middle two no. is 8*2=16, as each of the set no. is unqiue, so the middle to number is 6 and 10, _ _ 6 10 _ _ and as each no is not greater than 13 , the greatest no. is 13, so we have _ _ 6 10 _ 13 by subtraction, we have 48-13-16=19, we can have 9 between 10 and 13 , then 10 leave , we can make the least number by subtracting 8 from 10 , so we get 2 finally,