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# Math! xD

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Tim flew home from holiday with a heavy bag. With the first airline he flew, Tim had to pay \$20 to check his bag, plus \$22 for every kilogram that his bag was over the weight limit. The next flight was with another airline that had the same weight limit. Tim had to pay \$19 per kilogram that his bag was over the weight limit, in addition to the checked bag fee of \$32. By coincidence, the fees ended up being the same with both airlines. How large was each airline's fee? How far over the weight limit was the bag?

Each airline's fee was    \$, and the bag was       kilograms over the weight limit.

ItsTayha  May 10, 2017
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#1
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I don't know how to do this O-O'

Jelly  May 10, 2017
#2
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Let  k  represent the number of kilograms over the weight limit.

First airline:       Fee  =  \$20 + \$22k

Second airline:  Fee  =  \$32 + \$19k

Since the fees were equal:                 \$20 + \$22k  =  \$32 + \$19k

Subtracting \$19k from both sides:        \$20 + \$3k  =  \$32

Subtracing \$20 from both sides:                     \$3k  =  \$12

Dividing by 4:                                                      k  =  4      <--     the bag was 4 k overweight.

First airline:       Fee  =  \$20 + \$22k     --->     Fee  =  \$20 + \$22(4)  =  \$20 +  \$88  =  \$108

Second airline:  Fee  =  \$32 + \$19k     --->     Fee  =  \$32 + \$19(4)  =  \$32 +  \$76  =  \$108

geno3141  May 10, 2017

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