math y u do dis

They don't they are the same.

(2x-3)^4

The 4 line of pascals triangle is  14641

so

$(2x-3)^4\\=1*(2x)^4+4*(2x)^3*(-3)^1+6*(2x)^2*(-3)^2+4*(2x)^1*(-3)^3+1*(-3)^4\\ =1*16x^4+4*8x^3*-3+6*4x^2*9+4*2x^1*-27+1*81\\~\\ =1*16x^4+4*-24x^3\;\;+\;\;6*36x^2\;\;+\;\;4*-54x\;\;+\;\;1*81\\~\\ =16x^4-96x^3+216x^2-216x+81$

There could be careless errors but this should be the same as if you expand it in any other way.