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Three boys, Jason, Keith and Lucas, had equal number of coins. Jason had only twenty-cent coins. Keith and Lucas each had a mix of twenty-cent and one-dollar coins. Keith had 16 one-dollar coins while Lucas had 7 one-dollar coins.

 

(a) Of the three boys, who had the least amount of money and who had the most?

(b) What was the difference in the total value of Jason and Lucas' coins?

(c) Keith used half of his one-dollar coins and some of his twenty-cent coins to buy a book that cost $10.40. Then, he had 7/10 of his twenty-cent coins left. How many twenty-cent coins did Keith have at first?

 Aug 20, 2021
 #1
avatar+1496 
+1

Each boy had 56 coins.

 

a)  Jason       ($ 11.20)

 

b)    $ 5.60                 ( $16.80 - $11.20 )

 

c)    Keith had 40 twenty-cent coins at first.

 Aug 20, 2021
 #2
avatar+144 
+1

Show work plz!

RunningManZZ  Aug 20, 2021
 #3
avatar+1496 
+1

Very important text:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Keith and Lucas each had a mix of twenty-cent and one-dollar coins. Keith had 16 one-dollar coins...

(c) Keith used half of his one-dollar coins and some of his twenty-cent coins to buy a book that cost $10.40. Then, he had 7/10 of his twenty-cent coins left. How many twenty-cent coins did Keith have at first?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

1/  Keith had 16 one-dollar coins                                                                   => 16 coins

2/  He spent 8 one-dollar coins and 12 twenty-cent coins to buy a book.     =>  12 coins

3/  After he bought a book, Keith had 7/10 of his twenty-cent coins left.       =>  28 coins

                                                                                                        

12 / (3/10) = x / (7/10)         x = 28

 

Keith had 40 twenty-cent coins and 16 one=dollar coins.

 

Remember, all 3 boys had an equal number of coins. 

 

laugh

civonamzuk  Aug 21, 2021
 #4
avatar+144 
0

are you jugoslav?

RunningManZZ  Aug 22, 2021

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