2x^2+8x+8=0

A) 0; two imaginary solutions

B) 0; one real solution

C) 65; two real solutions

D) 0; two real solutions

Guest Mar 16, 2022

#1**+1 **

The **discriminant** of the quadratic equation is: b^{2} - 4·a·c where a, b, and c

are the coefficients of the x^{2}-term, the x-term, and the constant.

[provided that the equation is in this form: ax^{2} + bx + c = 0, which it is]

In this case: a = 2 b = 8 and c = 8

Place these values into the discriminant and solve.

If the result is any negative number, the quadratic has two imaginary solutions.

If the result is zero, the quadratic has one real solution.

If the result is andy positive number, the quadratic has two real solutions.

geno3141 Mar 16, 2022