2x^2+8x+8=0
A) 0; two imaginary solutions
B) 0; one real solution
C) 65; two real solutions
D) 0; two real solutions
+23245 The discriminant of the quadratic equation is: b2 - 4·a·c where a, b, and c
are the coefficients of the x2-term, the x-term, and the constant.
[provided that the equation is in this form: ax2 + bx + c = 0, which it is]
In this case: a = 2 b = 8 and c = 8
Place these values into the discriminant and solve.
If the result is any negative number, the quadratic has two imaginary solutions.
If the result is zero, the quadratic has one real solution.
If the result is andy positive number, the quadratic has two real solutions.
