In a lab experiment, 2400 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 19 hours. How long would it be, to the nearest tenth of an hour, until there are 3300 bacteria present?
Use \(N=N0\times 2^{t/19}\) where N = 3300 and N0 = 2400
Take logs and rearrange: \(t = 19\times \log_2(3300/2400)\)
I'll let you crunch the numbers.
