In how many ways can a family of six people be seated at a round table if the youngest kid must sit next to at least one of the parents?
i'm assuming there are 2 parents... Answer should be 5! - 3!3! = 120 - 36 = 84...correct me if im wrong
+129850 Assume that the child sits in seat 1
Count the number of ways that the child CANNOT sit next to either parent
They must sit in seats 3, 4 3,5 or 4,5
They can sit 2 ways in either seats 3,4 , 3,5 or 4,5 and for each of these, the other people (not counting the child) can be arranged in 3! ways = 3 (2)(3!) = 36 ways
Total arrangements = 5! = 120
So.....the ways the child CAN sit next to at lrast one of the parets = 120 - 36 = 84
{ The Guest and I agree !!! }
