4(3x^2 y^4)^3/(2x^3y^5)^4
Here is what it looks like
https://prnt.sc/pnu56m
+14915 Simplify 4(3x^2 y^4)^3/(2x^3y^5)^4
Hello Guest!
\( 4(3x^2 y^4)^3/(2x^3y^5)^4 \)
\(=\large \frac{4(27x^6y^{12})}{16x^{12}y^{20}}\)
\(=\large \frac{27}{4x^6y^8}\)
!
Sorry I don't understand what you did here
Like what are some fo the rules I was supposed to do while solving?
+118609 4(3x^2 y^4)^3/(2x^3y^5)^4
\(\frac{4(3x^2 y^4)^3}{(2x^3y^5)^4}\\~\\ \)
\(4*(3x^3y^4)^3\\ =4*(3*x^3*y^4)^3\\ =4*3^3*(x^3)^3*(y^4)^3\\ =4*27*x^{3*3}*y^{4*3}\\ =4*27*x^{9}*y^{12}\\\)
Now I have done what is necessary to simplify the top.
Now it is your turn to simplify the bottom.
After that you can put it back to one problem and cancel.
