4(3x^2 y^4)^3/(2x^3y^5)^4

Here is what it looks like

https://prnt.sc/pnu56m

Guest Oct 25, 2019

#1**+2 **

Simplify 4(3x^2 y^4)^3/(2x^3y^5)^4

**Hello Guest!**

\( 4(3x^2 y^4)^3/(2x^3y^5)^4 \)

\(=\large \frac{4(27x^6y^{12})}{16x^{12}y^{20}}\)

\(=\large \frac{27}{4x^6y^8}\)

!

asinus Oct 25, 2019

#2**+1 **

Sorry I don't understand what you did here

Like what are some fo the rules I was supposed to do while solving?

Guest Oct 25, 2019

#3**+1 **

4(3x^2 y^4)^3/(2x^3y^5)^4

\(\frac{4(3x^2 y^4)^3}{(2x^3y^5)^4}\\~\\ \)

\(4*(3x^3y^4)^3\\ =4*(3*x^3*y^4)^3\\ =4*3^3*(x^3)^3*(y^4)^3\\ =4*27*x^{3*3}*y^{4*3}\\ =4*27*x^{9}*y^{12}\\\)

Now I have done what is necessary to simplify the top.

**Now it is your turn to simplify the bottom.**

After that you can put it back to one problem and cancel.

Melody Oct 26, 2019