How many 4-digit numbers have the second digit even and the fourth digit at least twice the second digit?
OOps....was out on a run with the doggies and realized I made a mistake here...it is now corrected...
We have 9 possibilities for the first digit
The Third digit can be 0-9 (ten possibilities)
Three possible for the second digit 0 2 4
with 0 9 of the digits (1-9) can be fourth digit
with 2 the fourth digit can be 4 5 6 7 8 9 (six possibilities)
and with 4 only 8 9 can be fourth digit ( 6 or 8 cannot be the second digit because fourth needs to be 2x)
0 2 4
9 * 1 * 10 * 9 + 9 * 1 * 10 * 6 + 9 * 1 *10 * 2 = Well, I think you can do this math !