+38 If x and y are positive integers for which 3x + 2y + xy = 115, then what is x+y?
In this case, the value of x + y is 23. This can be determined by rearranging the equation 3x + 2y + xy = 115 to solve for x + y:
x + y = (115 - 2y)/(3 + y).
Substituting the given values for x and y, we have x + y = (115 - 2(2))/(3 + 2) = 23. Therefore, the value of x + y is 23.
+186 Factor as (x+2)(y+3)-6=115, thus (x+2)(y+3)=11^2 so x+2=11 and y+3=11, so x=9 and y=8 so x+y=17.
