Meyer rolls two fair, ordinary dice with the numbers  1,2,3,4,5,6on their sides. What is the probability that at least one of the dice shows a square number?


The only way for Meyer not to roll at least one square number is for non-square numbers to come up on both dice.


Two of the numbers on each die are squares: namely, 1 and 4. Four numbers on each die are not squares:2 , 3, 5, and 6. Thus there are  4*4 =16 ways for Meyer to roll a non-square number on each die, out of 36 equally likely outcomes for the pair of dice. The other  36-16 =20 outcomes each involve a square number showing on one or both dice. So, Meyer's probability of rolling at least one square number is 5/9.





Mary has six cards whose front sides show the numbers 1,2,3,4,5 and 6. She turns the cards face-down, shuffles the cards until their order is random, then pulls the top two cards off the deck. What is the probability that at least one of those two cards shows a square number?


Explain your solution. Is the answer the same as in part (a), or is it different? Why?

sageatron2000  May 16, 2018
edited by sageatron2000  May 17, 2018

0+0 Answers

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