+113 There are some stickers in albums A and B. 50% of the stickers in album A and 20% of the stickers in album B are round stickers. There is an equal number of square stickers in both albums. If there are 51 more round stickers in album A than in album B, how many stickers are there in both albums altogether?
+129905 This one is a little tricky !!!
In Album A....50% are Round and 50% are Square
Round = Square...... so R = S and the total number in album A = 2R
In Album B
It contains (R -51) Round stickers and S square stickers....so the total in this album =
(R - 51) + S
But S = R ....so.....
R - 51 + R → 2R - 51 = the total in album B
And we know that the Round stickers in B = R - 51 = 20% of the total....so....
R - 51 = .20 ( 2R - 51)
R - 51 = .4R - 10.2
R - .4R = 51 - 10.2
.6R = 40.8
R = 40.8 / .6 = 68
Album A contains 2R = 2(68) = 136 stickers
Album B contains 2(68) - 51 = 136 - 51 = 85 stickers
So 136 + 85 = 221 total stickers
