There are some stickers in albums A and B. 50% of the stickers in album A and 20% of the stickers in album B are round stickers. There is an equal number of square stickers in both albums. If there are 51 more round stickers in album A than in album B, how many stickers are there in both albums altogether?

tacoBRO1023 Jun 11, 2022

#1**+1 **

This one is a little tricky !!!

In Album A....50% are Round and 50% are Square

Round = Square...... so R = S and the total number in album A = 2R

In Album B

It contains (R -51) Round stickers and S square stickers....so the total in this album =

(R - 51) + S

But S = R ....so.....

R - 51 + R → 2R - 51 = the total in album B

And we know that the Round stickers in B = R - 51 = 20% of the total....so....

R - 51 = .20 ( 2R - 51)

R - 51 = .4R - 10.2

R - .4R = 51 - 10.2

.6R = 40.8

R = 40.8 / .6 = 68

Album A contains 2R = 2(68) = 136 stickers

Album B contains 2(68) - 51 = 136 - 51 = 85 stickers

So 136 + 85 = 221 total stickers

CPhill Jun 11, 2022