There are 100,000 people evenly distributed over 100 places.
What is the likelihood that 2 specific people are in the same place?
I will give this a go!
So you have 100 groups of 1,000 people each.
Let us designate the two persons "A" and "B".
"A" can be in any of the 100 groups, or 100/100.
The probability that "B" will be in a different group than "A" is 99/100.
So, the probability that "A" and "B" will be in different groups is: 100/100 x 99/100 =99%.
Therefore, the probability that they will be in the same group is: 1 - 99% =1%
