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Find the ordered pairs (m,n) where m, n are positive integers satisfying the following equation: 6mn = 27 + m - 2n.

 Apr 18, 2022
 #1
avatar+2455 
+1

The best way to solve this problem is by using Simon's Favorite Factoring Trick. 

 

We begin by isolating the coefficient. This gives: \(6mn+2n-m=27\)

 

Now, factor out \(n\)\(2n(3m+1)-m=27\)

 

We now need to factor out \(m\), in terms of \((3m+1)\), but, in order to do so, \(m\) must be a multiple of 3. 

 

To achieve this, we multiply the entire equation by 3:\(6n(3m+1)-3m=81\)

 

Now, we can factor out m as so: \(6n(3m+1) -1(3m+1)=-1+81\)

 

Simplifying, we get: \((6n-1)(3m+1)=80\)

 

We now need integer factors, so we try out each of the factor pairs of 80.

 

The only successful integer solution is \(\color{brown}\boxed{(5, 1)}\)

 Apr 18, 2022
 #2
avatar+115 
-4

hey builder boy can you help me learn some of these things

Kakashi  Apr 19, 2022

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