+0  
 
0
44
3
avatar+427 

Even: Choice 2

Odd: Choice 3

Neither even nor odd: Choice 1

 Dec 20, 2018
 #1
avatar+94275 
+2

Here's an easy way to determine even and odd

 

If I put  (-x) in for  x and I  come back to what I started with....then the function is even

 

If I put (-x) in for x and  all the original signs switch....the function is odd

 

So...first one

x^2 - 2x + 1

(-x)^2 - 2(-x) + 1   =   x^2 + 2x + 1

I don't come back with what I started with and all the signs are not switched...so...neither

 

Second one

x^2 + 1

(-x)^2 + 1   =  x^2 + 1 ....I end up with what I started with....so....even

 

Last one

-2x + 1

-2(-x) + 1  =    2x + 1.....I don't come back with what I started with and the signs are not all switched either....so.....neither!!!!

 

 

 

cool cool cool

 Dec 20, 2018
edited by CPhill  Dec 20, 2018
edited by CPhill  Dec 20, 2018
 #2
avatar+15316 
+1

I like that determination !     Thnx    ~EP

ElectricPavlov  Dec 20, 2018
 #3
avatar+94275 
0

Thanks, EP

 

Yeah....I remember using this method when I  tutored....it seems pretty easy....!!!!

 

 

cool cool cool

CPhill  Dec 20, 2018

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