Joe had some 20-cent and 50-cent coins. 7/8 of the total number of coins was 20-cent coins and the rest were 50-cent coins. After Joe spent some of his 50-cent coins worth $72.50 and 5/7 of the number of 20-cent coins, the number of coins left was 2/7 of the total number of coins at first. Find the total amount of money Joe had left?
The other person's answer is incorrect
Joe spent 50 worth = $72.50
Number of 50 cent coins spent = 72.50/0.50 = 145
Number of 20 cent coins he spent = 5/7 * 7/8x = 5/8x
(7/8x - 5/8x) + (1/8x - 145) = 2/7x
x = 1624
Number of 20 cent coins left = (7/8x - 5/8x) = 2/8x = 406
Number of 59 cent coins left = (1/8x - 145) = (1/8 * 1624 - 145) = 58
Amount Joe had left = 406 * 0.20 + 58 * 0.50 = $110.20
This is the correct answer
