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Philip determines the remainder of −32x^23+5x^7−3x^4+6x+1, using the remainder theorem.

 

A. Philip evaluates the numerator of the expression when x=−1. He finds the remainder of the division to be −24.

B. Philip evaluates the numerator of the expression when x=−1. He finds the remainder of the division to be 30.

C. Philip evaluates the numerator of the expression when x = 1. He finds the remainder of the division to be −24.

D. Philip evaluates the numerator of the expression when x = 1. He finds the remainder of the division to be 30.

 Sep 8, 2020
 #2
avatar+111172 
+1

sub the x value in and the value you get will be the remainder. 

 Sep 8, 2020

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