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The plot below shows the weight of  14 pumpkins Jack-O-Lantern farm.

 

https://prnt.sc/r579dh

 

lyde picked the lightest pumpkin. Koen picked the two heaviest pumpkins.

How much more do Koen's pumpkins combined weigh than Clyde's pumpkin weighs?
All measurements are rounded to the nearest 1/4 pound

 Feb 20, 2020

Best Answer 

 #1
avatar+278 
+1

Clyde's lightest pumpkins show that they are \(10\frac{3}{4}.\) Koen's heaviest pumpkins weigh \(17\frac{2}{4}\) each. Thus, \(17\frac{2}{4}\cdot2=35.\) Then, Clyde's pumpkins subtracted from Koen's pumpkins will be \(35-10\frac{3}{4}=\boxed{24\frac{1}{4}}.\)

 Feb 20, 2020
edited by DragonLord  Feb 20, 2020
 #1
avatar+278 
+1
Best Answer

Clyde's lightest pumpkins show that they are \(10\frac{3}{4}.\) Koen's heaviest pumpkins weigh \(17\frac{2}{4}\) each. Thus, \(17\frac{2}{4}\cdot2=35.\) Then, Clyde's pumpkins subtracted from Koen's pumpkins will be \(35-10\frac{3}{4}=\boxed{24\frac{1}{4}}.\)

DragonLord Feb 20, 2020
edited by DragonLord  Feb 20, 2020
 #2
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Excellent answer, DragonLord   !!!!

 

 

cool cool cool

CPhill  Feb 20, 2020

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