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Container A and B are identical containers with the same base. Container A is filled to the brim with water while Container B is empty. After 240 cm3 of water is poured into container B from container A, the depth of water in container B is 1/4 the depth of water in container A. If the height of the container is 25 cm, what is the base area of container B?

 Jun 11, 2022
 #1
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To make this easier, let's divide the height of each container  into 5ths

 

When   240 cm^3   of water is  poured into  container B from A,   the depth of the water in container A =  (4/5) its height and the depth of the water in  container B = 1/5 of its height......note that the depth of the water in B is 1/4 that of A

 

So......the depth of the water in B =  (1/5) (25 cm)  =  5cm   and B contains 240cm^3  of water

 

So....finding the base area is easy  (using the formula for the volume of a cylinder)

 

240 cm^3  = pi ( r^2) ( 5 cm)

 

240 cm^3  / 5 cm =  pi * r^2

 

48cm^2  = pi * r^2  =  the base area

 

 

cool cool cool

 Jun 11, 2022

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