+0

# math

0
524
2
+687

Anthony has a sink that is shaped like a half-sphere. The sink has a volume of 2000/3pi in^3. One day, his sink clogged. He has to use one of two cylindrical cups to scoop the water out of the sink. The sink is completely full when Anthony begins scooping.

One cup has a diameter of 4 in. and a height of 8 in. How many cups of water must Anthony scoop out of the sink with this cup to empty it? Round the number of scoops to the nearest whole number

Mar 1, 2019

#1
+23636
0

Volume of cylinder cup = pi r^2 h  = pi 2^2 8 = 32 pi    in^3

volume of sink/volume of cup = number of cups

2000/(3pi)  /   32 pi    =  2 scoops

If you meant the volume  is pi *2000/3       then  pi*   2000/3  /   32 pi =  21 scoops

Mar 1, 2019

#1
+23636
0

Volume of cylinder cup = pi r^2 h  = pi 2^2 8 = 32 pi    in^3

volume of sink/volume of cup = number of cups

2000/(3pi)  /   32 pi    =  2 scoops

If you meant the volume  is pi *2000/3       then  pi*   2000/3  /   32 pi =  21 scoops

ElectricPavlov Mar 1, 2019
#2
+235
+1

Rounding to the nearest whole number, I got 2. I could be wrong tho. 2000/3pi = 212.206 about. So that's the full volume of the sink. Divide that by the volume of the cylinder and you get 2.1108 about.

Idk how to do the estimate sign on here btw.

Hope this helps!

Mar 1, 2019