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how do you solve for x, when its x^2=x=30

 Mar 2, 2019
 #1
avatar+234 
+2

Are you sure you're copying the question right?

 Mar 2, 2019
 #2
avatar+101856 
+3

I'm going to guess that you meant

 

x^2 - x =  30          subtract 30 from both sides

 

x^2 - x -30 =  0      factor

 

(x - 6) ( x + 5) = 0

 

Set both factors to 0  and solve for x and we get that    x = 6    or x = -5

 

 

cool  cool cool

 Mar 2, 2019
 #3
avatar+18449 
+3

On my computer , the + and equal sign are the same key....

Soooooooo MAYBE you meant   x^2+x = 30

x^2  +x -30 = 0

 

(x-5)(x+6) = 0      means x = 5  or  -6      (the OPPOSITE of what CPhill found for the other equation)   cheeky

 Mar 2, 2019

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