+476 What are the solutions to the system of equations?
y=−x2−5x−6
x+y=−3
Choices:
(−3, 0) and (−1,−2)
(−3, 0) and (−2, 0)
(−3, 0) and (−2,−1)
(−2, 0) and (−1,−2)
+4624 I think you mean: y=x2−5x−6 and x+y=−3. Taking x to the other side in our second equation, we have y=−3−x . This means −x2−5x−6=−3−x, so by using the quadratic formula, we get x=−3,x=−1. .
From here, first by plugging x=−3 in the second equation to solve for y, we get −3+y=−3,y=−3+3,y=0. Consequently, by plugging in x=−1, we get −1+y=−3,y=−3+1,y=−2. Finally, our two ordered pairs are (−3,0),(−1,−2) , so (A) or the first option.
+4624 I think you mean: y=x2−5x−6 and x+y=−3. Taking x to the other side in our second equation, we have y=−3−x . This means −x2−5x−6=−3−x, so by using the quadratic formula, we get x=−3,x=−1. .
From here, first by plugging x=−3 in the second equation to solve for y, we get −3+y=−3,y=−3+3,y=0. Consequently, by plugging in x=−1, we get −1+y=−3,y=−3+1,y=−2. Finally, our two ordered pairs are (−3,0),(−1,−2) , so (A) or the first option.
