#1**+16 **

Okay. We are given that \(90^\circ = 12\) children.

Let's first solve for the mint portion. \(45^\circ\) is half of \(90^\circ\), so the number of children that like mint ice cream should also be half of the number of children who like vanilla, giving us \(\boxed 6\) children who like mint ice cream.

Next, let's solve for the angle measure of the strawberry portion of the pie chart. We are given that \(14\) children voted for strawberry. I'm going to use ratios to solve this one.

\(12 : 14 = 90 : x\).

\(12x = 1260\).

\(x = 105\).

So the angle measure of the strawberry portion is \(\boxed{105^\circ}\).

Finally, let's solve for the number of children who like chocolate ice cream. \(120\) is \(\frac{4}{3}\) of \(90\), so the number of children who like chocolate ice cream should also be \(\frac{4}{3}\) of the number of children who like vanilla ice cream.

\(12 \times \frac{4}{3} = 16\).

Therefore, \(\boxed{16}\) children like chocolate ice cream.

Hope that helps!

KnockOut Nov 3, 2018

#1**+16 **

Best Answer

Okay. We are given that \(90^\circ = 12\) children.

Let's first solve for the mint portion. \(45^\circ\) is half of \(90^\circ\), so the number of children that like mint ice cream should also be half of the number of children who like vanilla, giving us \(\boxed 6\) children who like mint ice cream.

Next, let's solve for the angle measure of the strawberry portion of the pie chart. We are given that \(14\) children voted for strawberry. I'm going to use ratios to solve this one.

\(12 : 14 = 90 : x\).

\(12x = 1260\).

\(x = 105\).

So the angle measure of the strawberry portion is \(\boxed{105^\circ}\).

Finally, let's solve for the number of children who like chocolate ice cream. \(120\) is \(\frac{4}{3}\) of \(90\), so the number of children who like chocolate ice cream should also be \(\frac{4}{3}\) of the number of children who like vanilla ice cream.

\(12 \times \frac{4}{3} = 16\).

Therefore, \(\boxed{16}\) children like chocolate ice cream.

Hope that helps!

KnockOut Nov 3, 2018