+1713 
This is the same program as CuteDramiones, I just need help, like a nudge, then If I still don't get it, a bigger hint pls... Or if you don't want to talk, the whole solution.
+129899 P(< 15 from Box A) = (14/20) = 7/10 (1)
P(even or > 25 from Box B) =
P(even from Box B) + P(>25 from Box B) - P(even and > 25 from Box B) =
(10/20) + (5/20) - (3/20) = 12/20 = 3/5 (2)
So.....the probability of (1) and (2) = 7/10 * 3/5 = 21 / 50
+1008 You didnt Cphills is like this
SpaceSpace
See
Hear is a answer from Cphill
P(< 15 from Box A) = (14/20) = 7/10 (1)
P(even or > 25 from Box B) =
P(even from Box B) + P(>25 from Box B) - P(even and > 25 from Box B) =
(10/20) + (5/20) - (3/20) = 12/20 = 3/5 (2)
So.....the probability of (1) and (2) = 7/10 * 3/5 = 21 / 50
See I hope this helps!
