John saves 5 fifty-cent coins in the first week. He saves 6 fifty-cent coins in the

second week. In the third week, he saves 7 fifty-cent coins and so on. How many

fifty-cent coins can John save altogether by the end of 10 weeks?

Guest Apr 6, 2021

#1**+1 **

If I understand the question correctly our equation is (**5***0.5) + (**6***0.5) + (**7***0.5) + (**8***0.5) + (**9***0.5) + (**10***0.5) + (**11***0.5) + (**12***0.5) + (**13***0.5) + (**14***0.5) = $47.5**. He saves 95 fifty-cent coins in 10 days **

itachiuchihakujo Apr 6, 2021

#2**+1 **

a_{n} = 5 + (n-1) Arithnetic Sequence

sum_{10} = n/2 ( a_{1}+a_{10})= 10/2 ( 5 + 14) = 190/2 = 95 coins saved in 10 weeks

ElectricPavlov Apr 6, 2021