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John saves 5 fifty-cent coins in the first week. He saves 6 fifty-cent coins in the 
second week. In the third week, he saves 7 fifty-cent coins and so on. How many 
fifty-cent coins can John save altogether by the end of 10 weeks?

 Apr 6, 2021
 #1
avatar+321 
+1

If I understand the question correctly our equation is (5*0.5) + (6*0.5) + (7*0.5) + (8*0.5) + (9*0.5) + (10*0.5) + (11*0.5) + (12*0.5) + (13*0.5) + (14*0.5) = $47.5.

He saves 95 fifty-cent coins in 10 days           

 Apr 6, 2021
edited by itachiuchihakujo  Apr 6, 2021
 #2
avatar+34390 
+1

an = 5 + (n-1)   Arithnetic Sequence

   sum10 = n/2 ( a1+a10)= 10/2 ( 5 + 14) = 190/2 = 95 coins saved in 10 weeks

 Apr 6, 2021

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