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how trasform I(z)=I(0)*e^ln(1/10)*z in a potencial equation??
 Oct 12, 2013
 #1
avatar+118654 
0
I am sorry I don't understand your question.

how trasform I(z)=I(0)*e^ln(1/10)*z in a potencial equation??

x(z)?
I(0)?

e ln(1/10) = 1/10
e and log e cancel each other out but that is all I can help with. I don't understand the rest of your question.
 Oct 12, 2013
 #2
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0
okey in the maths question I have:

I(z) = I(0) * e^(-a*z)

I found, a that in the first paragraph says that at Z = 1 the equation is 10%, but later said me that I have to transform this exponential equation to a potential equation.
 Oct 12, 2013
 #3
avatar+118654 
0
Okay, I still don't understand, maybe you are studying maths that I have not done or maybe the meaning just gets lost in the translation.
I have not heard the term potencial equation before, do you just mean an equation that is not exponential? (no powers)

Your original question was
how trasform I(z)=I(0)*e^ln(1/10)*z in a potencial equation?
I am going to assume l is a function.

I(z)=I(0) * e ln(1/10) * z

I(z)=I(0) * (1/10) * z

I(z)=I(0) * z * (1/10)

I(z)=I(0) * z / 10
-------------------------------

l(0) = l(0) * 0/10 = 0
so
I(z)=I(0) * z / 10 = 0*z/10 = 0

So, with my limited understanding of your problem I get an answer of 0
 Oct 13, 2013
 #4
avatar+118654 
0
Just in case you have already seen my answer, I did fix a little typo in the first line of the solution.
 Oct 13, 2013

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