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https://prnt.sc/p5weo9

 Sep 14, 2019

Best Answer 

 #1
avatar+681 
+1

\(2/5a+6 \begin{bmatrix} 3&\\ -2& \\7& \end{bmatrix} = \begin{bmatrix} 15& \\ -10 & \\35 \end{bmatrix}\)

we realize that the each element in the matrix was multiplied by 5 so a must be a value that will make 2/5a+6= 5 therefore a must be a negative reciprocal of 2/5 thus we will get -5/2 because that gives us -1 and when you add -1+6=5 which satisifes the equation. 

hope this helped. :) 

 Sep 14, 2019
 #1
avatar+681 
+1
Best Answer

\(2/5a+6 \begin{bmatrix} 3&\\ -2& \\7& \end{bmatrix} = \begin{bmatrix} 15& \\ -10 & \\35 \end{bmatrix}\)

we realize that the each element in the matrix was multiplied by 5 so a must be a value that will make 2/5a+6= 5 therefore a must be a negative reciprocal of 2/5 thus we will get -5/2 because that gives us -1 and when you add -1+6=5 which satisifes the equation. 

hope this helped. :) 

Nirvana Sep 14, 2019
 #2
avatar+681 
+1

also correct me if i am wrong.

Nirvana  Sep 14, 2019
 #3
avatar+106536 
+2

[(2/5)a + 6] * 3   = 15

 

(6/5)a + 18  =   15

 

(6/5)a  =  - 3

 

a  =   (-15/6)   =  (-5/2)

 

 

Check this in the other two  evaluations 

 

[ -1 + 6 ]  (-2)  =  [5] (-2)   =  -10

 

And

 

(-1 + 6 ] (7)  =  [5](7)  =  35

 

And Nirvava is correct  !!!!

 

 

 

cool cool cool

 Sep 14, 2019
 #4
avatar+681 
+1

yay!! :)) 

Nirvana  Sep 14, 2019

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