We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

Max gave 2/5 of his beans away to his brother, and consumed 1/3 of his beans. He takes the remaining amount of beans and places it evenly into 3 containers. If each container had 2 beans how many beans did he have to start (in the beginning)?

Guest May 10, 2017

#2**+1 **

Given the way the problem is written Guest#1 is correct!

However, if the problem should have said "Max gave 2/5 of his beans away to his brother, and consumed 1/3 of his ** remaining **beans. He takes the remaining amount of beans and places it evenly into 3 containers. If each container had 2 beans how many beans did he have to start (in the beginning)?", then:

Let B be the original number:

After giving away 2/5B max is left with 3/5B.

After eating 1/3 of this Max is left with (2/3)*3/5B → 2/5B

This equals 2*3 → 6

so 2/5B = 6

B = 6*5/2 → 15

So Max originally had 15 beans.

Alan May 11, 2017