Max gave 2/5 of his beans away to his brother, and consumed 1/3 of his beans. He takes the remaining amount of beans and places it evenly into 3 containers. If each container had 2 beans how many beans did he have to start (in the beginning)?

Guest May 10, 2017

#2**+1 **

Given the way the problem is written Guest#1 is correct!

However, if the problem should have said "Max gave 2/5 of his beans away to his brother, and consumed 1/3 of his ** remaining **beans. He takes the remaining amount of beans and places it evenly into 3 containers. If each container had 2 beans how many beans did he have to start (in the beginning)?", then:

Let B be the original number:

After giving away 2/5B max is left with 3/5B.

After eating 1/3 of this Max is left with (2/3)*3/5B → 2/5B

This equals 2*3 → 6

so 2/5B = 6

B = 6*5/2 → 15

So Max originally had 15 beans.

Alan May 11, 2017