Max gave 2/5 of his beans away to his brother, and consumed 1/3 of his beans. He takes the remaining amount of beans and places it evenly into 3 containers. If each container had 2 beans how many beans did he have to start (in the beginning)?
+33652 Given the way the problem is written Guest#1 is correct!
However, if the problem should have said "Max gave 2/5 of his beans away to his brother, and consumed 1/3 of his remaining beans. He takes the remaining amount of beans and places it evenly into 3 containers. If each container had 2 beans how many beans did he have to start (in the beginning)?", then:
Let B be the original number:
After giving away 2/5B max is left with 3/5B.
After eating 1/3 of this Max is left with (2/3)*3/5B → 2/5B
This equals 2*3 → 6
so 2/5B = 6
B = 6*5/2 → 15
So Max originally had 15 beans.
