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Max gave 2/5 of his beans away to his brother, and consumed 1/3 of his beans. He takes the remaining amount of beans and places it evenly into 3 containers. If each container had 2 beans how many beans did he have to start (in the beginning)?

 May 10, 2017
 #1
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He started with 22.5 beans. I am absolutely certain this is the correct answer.

 May 11, 2017
 #2
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Given the way the problem is written Guest#1 is correct!

 

However, if the problem should have said "Max gave 2/5 of his beans away to his brother, and consumed 1/3 of his remaining beans. He takes the remaining amount of beans and places it evenly into 3 containers. If each container had 2 beans how many beans did he have to start (in the beginning)?", then:

 

Let B be the original number:

 

After giving away 2/5B max is left with 3/5B.

 

After eating 1/3 of this Max is left with (2/3)*3/5B → 2/5B

 

This equals 2*3 → 6

 

so 2/5B = 6

 

B = 6*5/2  → 15

 

So Max originally had 15 beans.

 May 11, 2017

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