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Two sequences A={a0,a1,a2,} and B={b0,b1,b2,} are defined as follows:

 

a0=0, a1=1, an=an1+bn2forn2

 

b0=1, b1=2, bn=an2+bn1forn2

 

What is the remainder when a50+b50 is divided by 5?

 

 

 

Hey, I took the time to write this in LaTeX so yall can read it.

 Nov 2, 2020
 #1
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Using a computer program, a_{50} leaves a remainder of 1, and b_{50} leaves a remainder of 2, so a_{50} + b_{50} leaves a remainder of 3.

 Nov 2, 2020
 #2
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a(50) = It is simply the 50th Fibonacci number =12586269025

b(50) = It is the 52nd Fibonacci number             =32951280099

 

a(50)  +  b(50) =[12586269025 + 32951280099] mod 5 == 4

 Nov 2, 2020
 #3
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Have you written out the beginning of the sequence of yourself?

 

What did you do yourself before you asked for help?

 Nov 2, 2020

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