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# me confused

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A right hand tryangle has a base of 4 cm, the hight is 6cm how do you find the slant hight.

May 3, 2020

#1
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Pythagorean Theorem Time! $$a^2 + b^2 = c^2$$ (a = length of one leg, b = length of second leg, c = hypotenuse length)

$$4^2 + 6^2 = c^2$$

$$16 + 36 = c^2$$

$$52 = c^2$$

$$c = \sqrt{52} = \fbox{2\sqrt{13}}$$ is the slant height (the hypotenuse) :D

May 3, 2020
#2
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Thank you! it really helped

TacoBell  May 3, 2020