+51 Line BD bisects angle ABC, the measurement of ABD = 1/2y+10 degrees, and the measurment of DBC = y+4 degrees. Find the measurement of angle ABC.
+23252 Since BD bisects angle(ABC), angle(ABD) = angle(DBC).
½y + 10 = y + 4
Subtract ½y from both sides: 10 = ½y + 4
Subtract 4 from both sides: 6 = ½y
Multiply both sides by ½: 12 = y
So: angle(ABD) = ½y + 10 = ½(12) + 10 = 6 + 10 = 16
angle(DBC) = y + 4 = 12 + 4 = 16
Angle(ABC) = angle(ABD) + angle(DBC) = 16 + 16 = 32.
+23252 Since BD bisects angle(ABC), angle(ABD) = angle(DBC).
½y + 10 = y + 4
Subtract ½y from both sides: 10 = ½y + 4
Subtract 4 from both sides: 6 = ½y
Multiply both sides by ½: 12 = y
So: angle(ABD) = ½y + 10 = ½(12) + 10 = 6 + 10 = 16
angle(DBC) = y + 4 = 12 + 4 = 16
Angle(ABC) = angle(ABD) + angle(DBC) = 16 + 16 = 32.
+51 Thanks! That helped me out a ton, forgot how to do the whole thing. You made it pretty clear for me and now I can do the rest. Thanks again.
