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At a meeting, everyone shook hands with everybody else. There were 66 handshakes. How many people were in the room?

 Feb 20, 2016

Best Answer 

 #1
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The number of handshakes would be the sum of n+1 people. Forming the following sum.

1+2+3+4+.....+n

n(n+1)/2 which would equal 66 in this question.

 

n(n+1)/2 = 66

1/2(n^2+n) = 66

n^2+2n-132=0

Solving this quadratic gives the solution of n =11

 

Therefore the number of people at the meeting would be n+1 -> 11+1=12

 

12 people at the meeting

 Feb 20, 2016
 #1
avatar
+10
Best Answer

The number of handshakes would be the sum of n+1 people. Forming the following sum.

1+2+3+4+.....+n

n(n+1)/2 which would equal 66 in this question.

 

n(n+1)/2 = 66

1/2(n^2+n) = 66

n^2+2n-132=0

Solving this quadratic gives the solution of n =11

 

Therefore the number of people at the meeting would be n+1 -> 11+1=12

 

12 people at the meeting

Guest Feb 20, 2016

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