We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

for this question first i identified (r+1)^2 = r^2+2r+1

i subbed in r+1 into r which gave me f(r+1)= 2r^3 + 8r^2 + 13r + 6

then subtracted the expanded version of f(r) which is 2r^3 + 3r^2 + r

which at the end gave me 5r^2 + 12r + 6

i think the 5 in my answer should be 6

spot my mistake please.

YEEEEEET Dec 29, 2018

#1**+3 **

You are correct in your assumption.....

instead of 2 r^3 + 8r^2 + 13 r + 6 I get

2 r^3 +** 9**r^2 + 13r + 6 ....... So when you were expanding, you got something a little befuzzled.....look at it again....G'Luck !

ElectricPavlov Dec 29, 2018