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202
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79,141,238,355,401,?

Guest Jun 11, 2017

Best Answer 

 #2
avatar+26366 
+1

It's always possible to find another number in any sequence!  For example, consider the function:

 

f(n) = - (19/6)n4 + (175/6)n3 - (235/3)n2 + (421/3)n - 9

 

n        f(n)

1          79

2        141

3        238

4        355

5        401

6        209

 

Of course, this might not be the sequence the questioner had in mind!

Alan  Jun 11, 2017
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2+0 Answers

 #1
avatar+6900 
0

Does not have a sequence.

MaxWong  Jun 11, 2017
 #2
avatar+26366 
+1
Best Answer

It's always possible to find another number in any sequence!  For example, consider the function:

 

f(n) = - (19/6)n4 + (175/6)n3 - (235/3)n2 + (421/3)n - 9

 

n        f(n)

1          79

2        141

3        238

4        355

5        401

6        209

 

Of course, this might not be the sequence the questioner had in mind!

Alan  Jun 11, 2017

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