A mixture containing 4% saline solution is to be mixed with 2 quarts of a mixture which is 10% saline to obtain a solution which is 8% saline. How much of the 4% solution must be used?

Btw: No need to give me step by step. I only need the answer.

Guest Jul 28, 2021

edited by
Guest
Jul 28, 2021

#1**+1 **

amount of saline in ingredients = saline in final soln

x = 4% .04x

10% = 2 quarts = .10(2)

Final solution = .08 (2 + x)

.04x + .1(2) = .08 ( 2+x) solve for x quarts

ElectricPavlov Jul 28, 2021