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A mixture containing 4% saline solution is to be mixed with 2 quarts of a mixture which is 10% saline to obtain a solution which is 8% saline. How much of the 4% solution must be used?
 

Btw: No need to give me step by step. I only need the answer.

 Jul 28, 2021
edited by Guest  Jul 28, 2021
 #1
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amount of saline in ingredients = saline in final soln

 

x = 4%     .04x

10% = 2 quarts = .10(2)

Final solution =  .08 (2 + x)

 

.04x   + .1(2) = .08 ( 2+x)        solve for x quarts

 Jul 28, 2021

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