Solve the following system:
{-6 x-2 y = 20 | (equation 1)
x-y = -6 | (equation 2)
Add 1/6 × (equation 1) to equation 2:
{-(6 x)-2 y = 20 | (equation 1)
0 x-(4 y)/3 = -8/3 | (equation 2)
Divide equation 1 by 2:
{-(3 x)-y = 10 | (equation 1)
0 x-(4 y)/3 = -8/3 | (equation 2)
Multiply equation 2 by -3/4:
{-(3 x)-y = 10 | (equation 1)
0 x+y = 2 | (equation 2)
Add equation 2 to equation 1:
{-(3 x)+0 y = 12 | (equation 1)
0 x+y = 2 | (equation 2)
Divide equation 1 by -3:
{x+0 y = -4 | (equation 1)
0 x+y = 2 | (equation 2)
Collect results:
Answer: | {x = -4 and y=2
