#1**+1 **

n=1; a=(127 % n);printa,n; n++; if(n<200, goto1, discard=0;

Rem n

7 8

7 10

7 12

7 15

7 20

7 24

7 30

7 40

7 60

7 120

So, the ten numbers to the RHS.

Guest Apr 16, 2019

#2**+1 **

How many positive integers n satisfy 127 = 7 mod n? (n=1 is allowed)

127=7modn

127=kn+7 where k and n are integers and n is bigger than 7

120 = kn

prime factors of 120 are 2^3 *3*5

So what factors are bigger than 7

3 too little

5 too little

3*5 =15

2*5 =10

2*15 =30

4*3 = 12

4*5 =20

4*15 =60

8*3 =24

8*5 =40

8*15 =120

127 = 7 mod n?

10, 12, 15, 20, 24, 30, 40, 60, 120

So there are 9 of them

Melody Apr 16, 2019