Am I correct?

I am not sure about this question

Am I correct?

I'm not able to figure out the answer for this question

I wasn't able to answer this

Help will be very appreciated

cerenetie Mar 9, 2019

#1**+2 **

Problem 1 you are correct

Problem 3 you are not correct (what is 540/2?)

Problem 2 - come on... it's almost trivial. What is f(-2)? what is g(-2)?

Rom Mar 9, 2019

#3**+1 **

**Hi Cerenity,**

Yes i understand this may not be trivial for you but

**Can you answer Rom's question please.**

What is f(-2)? what is g(-2)?

g(x) is in the table of values. Can you see what g(-2) is?

\(f(x)=3-x^2\)

To find f(-2) you have to replace the x with -2. Can you do that for us please.

You will be more likely to get it right if you put the -2 in brackets like this (-2)

Melody
Mar 12, 2019

#4**+2 **

1) is the domain of function A is the set of real numbers greater than 0

the domain of function B is the set of real numbers greater than or equal to 1

2) f(-2) = g(-2)

3) the distance plane A traveled in 1h is greater than the distance plane B traveled in 1h

4) Function A has a vertical asympotote at x=3

Function A has a vertical asympotote at x= 4

5) both functions have one negative and one positive x-intercept

cerenetie
Mar 14, 2019

#5**+1 **

**Thanks for your response Cerentie.**

To be honest I am reather confused because there are so many questions here all together.

**Next time just put one question per post. :)**

But I am going to look at question 2 for you. Here it is:

\(f(x)=3-x^2\\ so\\ f(-2)=3-(-2)^2\\ \text{see I have swapped the x for -2}\\ f(-2)=3-(-2*-2)\\ f(-2)=3-(4)\\ f(-2)=3-4\\ f(-2)=-1\\\)

g(x)= well you will have to read this one off the table.

for g(-2) you go down to x=-2 then across and you can see that g(-2)=-1

so

f(-2)=g(-2)=-1

Melody
Mar 15, 2019