+642
Am I correct?
I am not sure about this question
Am I correct?
I'm not able to figure out the answer for this question
I wasn't able to answer this
Help will be very appreciated
+6248 Problem 1 you are correct
Problem 3 you are not correct (what is 540/2?)
Problem 2 - come on... it's almost trivial. What is f(-2)? what is g(-2)?
+118608 Hi Cerenity,
Yes i understand this may not be trivial for you but
Can you answer Rom's question please.
What is f(-2)? what is g(-2)?
g(x) is in the table of values. Can you see what g(-2) is?
\(f(x)=3-x^2\)
To find f(-2) you have to replace the x with -2. Can you do that for us please.
You will be more likely to get it right if you put the -2 in brackets like this (-2)
+642 1) is the domain of function A is the set of real numbers greater than 0
the domain of function B is the set of real numbers greater than or equal to 1
2) f(-2) = g(-2)
3) the distance plane A traveled in 1h is greater than the distance plane B traveled in 1h
4) Function A has a vertical asympotote at x=3
Function A has a vertical asympotote at x= 4
5) both functions have one negative and one positive x-intercept
+118608 Thanks for your response Cerentie.
To be honest I am reather confused because there are so many questions here all together.
Next time just put one question per post. :)
But I am going to look at question 2 for you. Here it is:
\(f(x)=3-x^2\\ so\\ f(-2)=3-(-2)^2\\ \text{see I have swapped the x for -2}\\ f(-2)=3-(-2*-2)\\ f(-2)=3-(4)\\ f(-2)=3-4\\ f(-2)=-1\\\)
g(x)= well you will have to read this one off the table.
for g(-2) you go down to x=-2 then across and you can see that g(-2)=-1
so
f(-2)=g(-2)=-1
