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# models algebra

+1
212
5
+623

Am I correct?

Am I correct?

I'm not able to figure out the answer for this question

I wasn't able to answer this

Help will be very appreciated

Mar 9, 2019

#1
+6046
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Problem 1 you are correct

Problem 3 you are not correct (what is 540/2?)

Problem 2 - come on... it's almost trivial.  What is f(-2)?  what is g(-2)?

Mar 9, 2019
#2
+623
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trivial? it was pretty hard for me

cerenetie  Mar 12, 2019
#3
+105895
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Hi Cerenity,

Yes i understand this may not be trivial for you but

What is f(-2)?  what is g(-2)?

g(x) is in the table of values.  Can you see what g(-2) is?

$$f(x)=3-x^2$$

To find f(-2)  you have to replace the x with -2.   Can you do that for us please.

You will be more likely to get it right if you put the -2 in brackets like this  (-2)

Melody  Mar 12, 2019
#4
+623
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1) is the domain of function A is the set of real numbers greater than 0

the domain of function B is the set of  real numbers greater than or equal to 1

2) f(-2) = g(-2)

3) the distance plane A traveled in 1h is greater than the distance plane B traveled in 1h

4) Function A has a vertical asympotote at x=3

Function A has a vertical asympotote at x= 4

5) both functions have one negative and one positive x-intercept

cerenetie  Mar 14, 2019
#5
+105895
+1

To be honest I am reather confused because there are so many questions here all together.

Next time just put one question per post. :)

But I am going to look at question 2 for you.  Here it is:

$$f(x)=3-x^2\\ so\\ f(-2)=3-(-2)^2\\ \text{see I have swapped the x for -2}\\ f(-2)=3-(-2*-2)\\ f(-2)=3-(4)\\ f(-2)=3-4\\ f(-2)=-1\\$$

g(x)= well you will have to read this one off the table.

for g(-2)  you go down to x=-2 then across and you can see that g(-2)=-1

so

f(-2)=g(-2)=-1

Melody  Mar 15, 2019