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nWhat does this equation mean: 

$$|a-b| \equiv 2 (mod 3)$$

Examples are:

 $$|1-6| \equiv 2 (mod 3)$$ 

 $$|1-5| \not\equiv 2 (mod 3)$$

 Jan 7, 2015

Best Answer 

 #1
avatar+118609 
+5

$$|1-6| \equiv 2 (mod 3)$$

This is true because |1-6|=5

and 5 divided by 3 is  1 remainder 2

2 is the remainder.

Modular arithmetic is only concerned with the remainder.

 

So I could say that

|a-b|-3n=2        where     $$n\in J \ge 0$$

.
 Jan 7, 2015
 #1
avatar+118609 
+5
Best Answer

$$|1-6| \equiv 2 (mod 3)$$

This is true because |1-6|=5

and 5 divided by 3 is  1 remainder 2

2 is the remainder.

Modular arithmetic is only concerned with the remainder.

 

So I could say that

|a-b|-3n=2        where     $$n\in J \ge 0$$

Melody Jan 7, 2015

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