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The solution of $8x+1 \equiv 5$ (mod $12$) is $x \equiv a$ (mod $m$) for some positive integers $m \geq 2$ and $a

 Jun 18, 2021
 #1
avatar+366 
+1

Already been answered I believe: https://web2.0calc.com/questions/the-solution-of-8x-1-5-mod-12-is-x-a-mod-m-for-some 

 

I'm back babyyyyyy

 Jun 18, 2021
 #2
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I meant to type

 

The solution of $8x + 1 \equiv 5$ (mod $12$) is $x \equiv a$ (mod $m$) for some positive integers $m \geq 2$ and $a < m$. Find $a+m$

Guest Jun 18, 2021
 #3
avatar+366 
+2

The solution gives both A and M. I suggest you read over the solution, heureka did an amazing job on it :)

Badada  Jun 18, 2021
 #4
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Well, it seems the solution is that $m$ is nonnegative and is always a multiple of $3$. And $a = -1$, would this mean the answer would be $2$ or $5$ or $8$ etc.. ? Which of these is correct?

Guest Jun 18, 2021

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