Hi, could someone help me with this problem?
Given \(a \equiv 1 \pmod{7}\), \(b \equiv 2 \pmod{7}\), and \(c \equiv 6 \pmod{7}\), what is the remainder when \(a^{81} b^{91} c^{27}\) is divided by 7?
Thank you so much!
By inspection, the simplest solution is:
a =1, b = 2 and c = 6 and: [1^81*2^91*6^27] mod 7 = 5
The full solution is: a = 7 + 1 =8, b =7 + 2 =9 and c =7 + 6 =13 and [8^81*9^91*13^27] mod 7 = 5
+284 
